3

I got the transaction ID, why can't I find this transaction?id:onivQ7UehosXojRz6afTR7FZ9L3GfyLrkQa3G6J5rLys6qYoPW9 It should be that the transaction was not broadcast, but how can I find out why? Interface ‘/injection‘ return is successful

my operation is {u'branch': u'BMHqTybVHTwZcjFBL9zM3NRtBeN3VD6BNPukCmZf8JfTLKSFJG4', u'contents': [{u'source': u'tz1cxTyu7dwLUvXKt4mE85Rwr1XLB9byY2Vc', u'kind': u'transaction', u'fee': u'1607', u'storage_limit': u'60000', u'destination': u'tz1RVjS45cLxJHbQNQfvEf9u8ASkv5CC4hmp', u'amount': u'320000', u'gas_limit': u'800000', u'counter': '1505527'}]}

2
  • How did you try to inject it? Did you get any error message?
    – Arthur B
    Jun 24, 2019 at 8:39
  • I tried it again, no error message. And the log looks normal. Jun 24 16:57:02 - prevalidator.NetXdQprcVkpa.Pt24m4xiPbLD_1: injecting operation op5u2L4oB1BnpNWxRVrbjbfEwrX8v4UDYu6R87jCVtfUcQSbdgG Jun 24 16:57:02 - prevalidator.NetXdQprcVkpa.Pt24m4xiPbLD_1: Pushed: 2019-06-24T08:57:02-00:00, Treated: 2019-06-24T08:57:02-00:00, Completed: 2019-06-24T08:57:02-00:00
    – taozi
    Jun 24, 2019 at 9:41

1 Answer 1

3

Technically there's nothing wrong with your transaction and it didn't fail. But no baker wanted to (by default) include it in a block because of the low fee in relation to the gas & storage limits. So after 50 minutes it was cleared from mempool. There's no reason to set gas & storage limit to the maximum values possible in this case. You can find some recommended values to use here:

| Operation     | Gas       | Fees          | Burn              |
|-------------- |-------    |-----------    |----------------   |
| transfer 1ꜩ   | 10200     | 0.001281ꜩ     | 0 or 0.257 (*)    |
| transfer 1Mꜩ  | 10200     | 0.001284ꜩ     | 0 or 0.257 (*)    |
| origination   | 10000     | 0.001265ꜩ     | 0.257             |
| delegation    | 10000     | 0.001257ꜩ     | 0                 |
| revealing     | 10000     | 0.001268ꜩ     | 0                 |

http://tezos.gitlab.io/master/protocols/004_Pt24m4xi.html

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.